Berapa hasil dari nilai tan (135°-120°)=

nilai tan (135°-120°)=

Jawaban

tan (135°-120°) = tan 15°

= tan (45° – 30°)

 

tan (A-B) = (tan A – tan B)/(1+tan A·tan B)

 

tan (45° – 30°) = (tan 45° – tan 30°)/(1+tan 45°·tan 30°)

= (1 – 1/3 √3) / (1 + 1 · 1/3 √3)

= (1 – √3/3) / (1 + √3/3)

= [(3 – √3)/3] / [(3 + √3)/3]

= (3 – √3) / (3 + √3)

= (3 – √3) / (3 + √3) × (3 – √3)/(3 – √3)

= (9 – 6√3 + 3) / (9 – 3)

= (12 – 6√3)/6

= 2 – √3

 

Jadi, tan (135°-120°) = 2 – √3

Originally posted 2022-12-07 16:48:01.